Code Issues specific to operators
An operator is a member that defines the meaning of applying a particular expression operator to instances of a class or structure. Three kinds of operators can be defined: unary operators, binary operators, and conversion operators. All operators have must be declared according to the language specification.
For example, C# allows you to overload operators by defining static member functions using the operator keyword. Not all operators can be overloaded, and others have restrictions. For example, the signature of an operator should consist of the name of the operator and the type of each of its formal parameters, considered in left to right order. The signature of an operator specifically does not include the result type.
CodeRush includes several code issues that make it possible to declare operators without violating the operator declaration rules at the coding stage.
Here they are:
Operator cannot be abstract
Cause:
Operators must always be implemented. It is now allowed to mark operators with an ‘abstract‘ keyword. If an operator is marked as an ‘abstract‘, the error is shown.
Sample:
How to fix:
- Remove the ‘abstract’ modifier:
Operator cannot have the ‘params’ parameter
Cause:
Operators must have an unchanging number of parameters. You cannot have an undefined number of parameters for an operator by using the ‘params‘ keyword.
Sample:
How to fix:
- Remove the ‘params’ parameter:
Operator must be declared static and public
Cause:
According to the language specification, operators are declared as a static member with a ‘public‘ visibility modifier.
Sample:
How to fix:
- Mark the operator member as static and public:
Operator must declare a body
Cause:
Operators not marked with the external modifier must declare a member body. Operators without a code body will be highlighted as an error.
Sample:
How to fix:
- Declare the body of the operator:
Overloaded unary operator takes one parameter
Cause:
Implicit and explicit unary operators must accept a single parameter. If unary operator takes more than one parameter, an error is shown.
Sample:
How to fix:
- Remove the redundant parameter, e.g.,:
